MODULE M1.1: THE FOUNDATIONS

Complete Number Sets, Algebra, & Equations

The ultimate, comprehensive guide to IMAT mathematical foundations. We explore the complete hierarchy of number sets, advanced factorization techniques, exhaustive equation solving, and the rigorous logic required for inequalities.

Part 1: The Ultimate Hierarchy of Numbers

Before manipulating numbers through algebraic operations, we must precisely define what species of numbers we are dealing with. Mathematics categorizes numbers into distinct sets, each expanding upon the limitations of the previous one. Understanding these definitions is strictly required for logical reasoning questions.

Hierarchy of Number Sets Complex (ℂ) (e.g., $2+3i, 5i$) Real (ℝ) Irrational (I) (e.g., $\pi, \sqrt{2}, e$) Rational (ℚ) (e.g., $1/2, -0.75, 0.\bar{3}$) Integers (ℤ) (...-2, -1, 0, 1, 2...) Natural (ℕ) (1, 2, 3...)
Figure 1.1: The nested sets of numbers. Note that a Natural number is automatically an Integer, a Rational number, a Real number, and technically a Complex number (with an imaginary part of zero).
  • Natural Numbers ($\mathbb{N}$): The most basic numbers used for counting items. Typically defined as $\{1, 2, 3, 4, ...\}$. Note that some mathematical conventions include zero in this set, but strictly speaking, the counting numbers start at 1.
  • Integers ($\mathbb{Z}$): We introduce zero and the concept of negative quantities (debt, temperature below zero). The set is $\{..., -3, -2, -1, 0, 1, 2, 3, ...\}$.
  • Rational Numbers ($\mathbb{Q}$): The word rational stems from "ratio". Any number that can be expressed as a perfect ratio of two integers $\frac{p}{q}$ (where $q \neq 0$) is rational. This powerful set includes all integers (since $5 = \frac{5}{1}$), terminating decimals ($0.25 = \frac{1}{4}$), and infinitely repeating decimals.
  • Irrational Numbers: Numbers that absolutely cannot be expressed as a simple fraction. Their decimal expansions are both non-terminating and non-repeating. Classic examples include $\sqrt{2}, \sqrt{3}, \pi$, and Euler's number $e$.
  • Real Numbers ($\mathbb{R}$): The complete union of Rational and Irrational numbers. Every single point on an infinitely long, continuous number line corresponds to exactly one Real number.

1.1 Prime Numbers & Factorization

Within the set of Natural numbers, we distinguish between Prime and Composite numbers. A Prime Number is a natural number strictly greater than 1 that has exactly two distinct positive divisors: 1 and itself. (e.g., 2, 3, 5, 7, 11, 13, 17...).

A Composite Number has more than two divisors. The Fundamental Theorem of Arithmetic states that every integer greater than 1 either is a prime itself or can be represented uniquely as a product of prime numbers. This is called Prime Factorization.

Example: Prime Factorization and LCM / GCD

Find the Greatest Common Divisor (GCD) and Lowest Common Multiple (LCM) of 60 and 72.

  1. Factorize 60:
       60 = 6 × 10 = (2 × 3) × (2 × 5) = $2^2 \times 3^1 \times 5^1$
  2. Factorize 72:
       72 = 8 × 9 = $(2 \times 2 \times 2) \times (3 \times 3)$ = $2^3 \times 3^2$
  3. Greatest Common Divisor (GCD): Take the lowest power of common prime factors.
       GCD = $2^2 \times 3^1 = 4 \times 3 = \mathbf{12}$
  4. Lowest Common Multiple (LCM): Take the highest power of all prime factors present.
       LCM = $2^3 \times 3^2 \times 5^1 = 8 \times 9 \times 5 = \mathbf{360}$

Note: Finding the LCM is the fundamental step for adding or subtracting fractions with different denominators.

1.2 Converting Repeating Decimals to Fractions

Proof: Repeating Decimals are Rational

Prove that $x = 2.141414...$ (written as $2.\overline{14}$) is a rational number.

  1. Let the variable $x$ represent the repeating decimal:
       $x = 2.141414...$
  2. Because exactly 2 digits repeat ("14"), we multiply the entire equation by $10^2$ (which is 100) to shift the decimal point exactly one full repeating cycle to the right:
       $100x = 214.141414...$
  3. Now, subtract the original equation from this new equation. The infinite repeating decimal tails will perfectly cancel each other out:
        $100x = 214.141414...$
    -      $x =   2.141414...$
         $99x = 212$
  4. Solve algebraically for $x$:
       $x = \frac{212}{99}$

Because $2.1414...$ can be perfectly represented as the ratio of two integers (212 and 99), it is by definition a Rational number.

1.3 Scientific Notation (Standard Form)

Scientific notation is a method for expressing extremely large or extremely small numbers concisely. It is written in the form $A \times 10^n$, where $1 \le |A| < 10$ and $n$ is an integer.

  • Large numbers: Move the decimal to the left, and $n$ is positive.
    Example: $4,500,000 = 4.5 \times 10^6$.
  • Small numbers: Move the decimal to the right, and $n$ is negative.
    Example: $0.000032 = 3.2 \times 10^{-5}$.
IMAT Challenge

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Official Paper: 2023 - Q49

Find the set of real solutions of this inequation: $$2x^2 - 6x + 5 \ge 0$$
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Official Paper: 2018 - Q53

The equation below has two roots. What is the sum of the two roots? $$ \frac{x+4}{x+1} = x $$

Part 2: Indices, Radicals, and Rationalization

Indices (exponents) and radicals (roots) are two sides of the exact same mathematical coin. An index denotes repeated multiplication, while a radical asks for the base that was multiplied. Mastery of the laws governing these operations is non-negotiable for algebra.

The Universal Laws of Indices
  • Multiplication Law:
       $a^m \cdot a^n = a^{m+n}$
  • Division Law:
       $a^m \div a^n = a^{m-n}$
  • Power of a Power Law:
       $(a^m)^n = a^{mn}$
  • Power of a Product Law:
       $(ab)^n = a^n b^n$
  • Power of a Quotient Law:
       $(\frac{a}{b})^n = \frac{a^n}{b^n}$
  • Zero Index Rule:
       $a^0 = 1$ (for $a \neq 0$)
  • Negative Index Rule:
       $a^{-n} = \frac{1}{a^n}$
  • Fractional Index Rule (The Bridge to Radicals):
       $$a^{\frac{m}{n}} = \sqrt[n]{a^m} = (\sqrt[n]{a})^m$$

2.1 Operations with Radicals

You can only add or subtract radicals if they have the exact same radicand (the number inside the root) and the same index. This is similar to combining like terms in algebra ($2x + 5x = 7x$).

Addition and Subtraction of Radicals

Correct: $3\sqrt{5} + 4\sqrt{5} = 7\sqrt{5}$

Incorrect: $\sqrt{2} + \sqrt{3} \neq \sqrt{5}$. (These are unlike terms and cannot be combined. $\sqrt{2} + \sqrt{3}$ is the simplest form).

However, always check if radicals can be simplified first to reveal hidden like terms. For example: $\sqrt{18} + \sqrt{50} = \sqrt{9 \times 2} + \sqrt{25 \times 2} = 3\sqrt{2} + 5\sqrt{2} = 8\sqrt{2}$.

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Official Paper: 2022 - Q51

Evaluate: $$\sqrt[3]{\frac{(9\times10^{4})^{2}-10^{8}+1.2\times10^{11}}{10^{-1}-9.8\times10^{-2}}}$$
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Official Paper: 2017 - Q55

Which one of the following is an expression for the mean of $ x/3 $, $ x $, and $ x+6 $?

2.2 Rationalizing the Denominator

In mathematics, it is standard convention to remove irrational numbers (roots) from the denominator of a fraction. This process is called rationalization. We achieve this by multiplying the fraction by a strategic form of the number $1$.

  • Case 1: Single Term Denominator. If the denominator is a simple square root, multiply the numerator and the denominator by that exact square root.
    Example: $$ \frac{7}{\sqrt{3}} = \frac{7}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{7\sqrt{3}}{(\sqrt{3})^2} = \frac{7\sqrt{3}}{3} $$
  • Case 2: Binomial Denominator. If the denominator is an expression with two terms (like $a + \sqrt{b}$), you must multiply the numerator and denominator by its Conjugate (change the middle sign to $a - \sqrt{b}$). This exploits the difference of squares algebraic identity $(x-y)(x+y) = x^2 - y^2$ to eliminate the square roots entirely.

Example: Rationalize the Binomial Denominator

Simplify the expression: $\frac{2\sqrt{2}}{5 - \sqrt{7}}$

Step 1: Identify the conjugate of the denominator $(5 - \sqrt{7})$. The conjugate is $(5 + \sqrt{7})$.

Step 2: Multiply both the numerator and denominator by this conjugate.

$$ \frac{2\sqrt{2}}{5 - \sqrt{7}} \cdot \frac{5 + \sqrt{7}}{5 + \sqrt{7}} = \frac{2\sqrt{2}(5 + \sqrt{7})}{5^2 - (\sqrt{7})^2} = \frac{10\sqrt{2} + 2\sqrt{14}}{25 - 7} = \frac{10\sqrt{2} + 2\sqrt{14}}{18} $$

Step 3: Factor out common terms and simplify the fraction. We can divide the numerator and denominator by 2.

$$ \frac{2(5\sqrt{2} + \sqrt{14})}{18} = \frac{5\sqrt{2} + \sqrt{14}}{9} $$

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Official Paper: 2021 - Q54

Find the complete set of values of x which satisfy the inequality: $$\frac{1}{2}(2x+3) - \frac{2}{3}(x+1) \lt 2x$$
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Official Paper: 2017 - Q60

How many ways are there to order the letters 'AABBC'?

2.3 Advanced Technique: Unnesting Double Radicals

An expression nested inside another root, like $\sqrt{A \pm \sqrt{B}}$, can sometimes be simplified into the much cleaner form $\sqrt{a} \pm \sqrt{b}$. The trick relies directly on reversing the binomial expansion formula: $(\sqrt{a} \pm \sqrt{b})^2 = a + b \pm 2\sqrt{ab}$.

The Golden Rule for Double Radicals

To simplify an expression into the form $\sqrt{X \pm 2\sqrt{Y}}$, you absolutely must have a coefficient of exactly 2 in front of the inner root. Once you have that "2", you simply find two numbers $a$ and $b$ such that:

  • The sum $a + b = X$
  • The product $a \cdot b = Y$

Once found, the simplified form is $\sqrt{a} \pm \sqrt{b}$. Crucial Note: Always write the larger number first if dealing with subtraction to ensure a positive result!

Example: Unnesting $\sqrt{11 - \sqrt{112}}$

  1. Create the "2": We must extract a 4 from the inner root 112 because $\sqrt{4}=2$.
       $\sqrt{112} = \sqrt{4 \times 28} = 2\sqrt{28}$.
       The expression is now rewritten as: $\sqrt{11 - 2\sqrt{28}}$.
  2. Find the numbers: We need two numbers that add up to 11 and multiply together to make 28.
       Let's list factor pairs of 28: (1, 28), (2, 14), (4, 7).
       The pair $4$ and $7$ works perfectly because $4 + 7 = 11$.
  3. Apply the rule: Write the roots, placing the larger number first.
       $\sqrt{7} - \sqrt{4}$
  4. Final Simplification: We know that $\sqrt{4} = 2$.
       The final answer is $\mathbf{\sqrt{7} - 2}$.

Part 3: Comprehensive Polynomial Expansion

Expansion is the process of multiplying out brackets. Memorizing these standard expansions saves critical time during the exam. They form the foundational vocabulary of all advanced algebra.

The Ultimate Algebraic Expansion Cheat Sheet
  • Quadratic Expansions:

    Perfect Square (Sum): $(a + b)^2 = a^2 + 2ab + b^2$

    Perfect Square (Difference): $(a - b)^2 = a^2 - 2ab + b^2$

    Difference of Squares: $(a + b)(a - b) = a^2 - b^2$

    Square of a Trinomial: $(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca$


  • Cubic Expansions:

    Perfect Cube (Sum): $(a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3$

    Perfect Cube (Difference): $(a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3$

    Sum of Cubes: $a^3 + b^3 = (a + b)(a^2 - ab + b^2)$

    Difference of Cubes: $a^3 - b^3 = (a - b)(a^2 + ab + b^2)$

3.1 Geometric Visualization of Expansion

Algebraic identities are not arbitrary rules; they describe fundamental geometric realities. Let us visualize why $(a+b)^2 = a^2 + 2ab + b^2$ by looking at the area of a square.

Geometric Proof of the Perfect Square Expansion

$a^2$ $ab$ $ab$ $b^2$ a b a b
Figure 3.1: The total area of the large square is $(a+b) \times (a+b)$. This total area is exactly equal to the sum of the areas of its four internal geometric parts: one large square ($a^2$), two identical rectangles ($ab + ab = 2ab$), and one small square ($b^2$).

3.2 Pascal's Triangle for Higher Powers

If you need to expand $(a+b)^4$ or higher, memorizing formulas becomes impractical. Pascal's Triangle provides the exact coefficients needed for any binomial expansion $(a+b)^n$.

To build the triangle, start with 1 at the top. Every number below is the sum of the two numbers directly above it. The row index $n$ (starting at $n=0$ for the top row) corresponds to the power of the binomial.

Pascal's Triangle

1 n=0: (a+b)⁰ 1 1 n=1: (a+b)¹ 1 2 1 n=2: (a+b)² 1 3 3 1 n=3: (a+b)³ 1 4 6 4 1 n=4: (a+b)⁴
Figure 3.2: Notice how $3 + 3 = 6$. For $(a+b)^4$, the coefficients are 1, 4, 6, 4, 1. Therefore, $(a+b)^4 = 1a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + 1b^4$. As you move across the terms, the power of $a$ decreases while the power of $b$ increases.
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Official Paper: 2025 - Q51

The trinomial is equal to: $$a^2 - 4ab + 4b^2$$
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Official Paper: 2023 - Q50

The ratio of sugar to flour in a mixture is 1:5. After 1kg of sugar and 2kg of flour are added, the ratio changes to 2:5. A further 1kg of sugar and 2kg of flour are added. What is the new ratio?
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Official Paper: 2018 - Q60

Evaluate: $$ (3\times10^3)^3 \times (2\times10^{-5}) $$

Part 4: The Art and Strategy of Factoring

Factoring takes an expanded polynomial and breaks it down into a product of simpler parentheses. It is the exact reverse of expansion and is the most critical skill for solving equations. When faced with an expression to factor, you must follow this strict hierarchy of attack:

  1. 1. Greatest Common Factor (GCF): Always check for this first before applying any complex formulas.
    Solve: $12x^3y^2 - 18x^2y^3$
    The GCF of the numbers is 6. For variables, take the lowest power: $x^2$ and $y^2$.
    Result: $6x^2y^2(2x - 3y)$
  2. 2. Recognize Standard Formulas: Look for patterns from Part 3.
    Difference of Squares: $49x^2 - 25 = (7x - 5)(7x + 5)$
    Sum of Cubes: $8x^3 + 27 = (2x)^3 + 3^3 = (2x + 3)(4x^2 - 6x + 9)$
  3. 3. Factoring by Grouping (4 or more terms): Group terms strategically to extract a common binomial bracket.
    Expression: $x^3 + 2x^2 - 4x - 8$
    Group first two and last two: $(x^3 + 2x^2) - (4x + 8)$
    Factor each group: $x^2(x + 2) - 4(x + 2)$
    Extract common bracket: $(x + 2)(x^2 - 4)$
    Factor the remaining difference of squares: $\mathbf{(x + 2)(x - 2)(x + 2) = (x + 2)^2(x - 2)}$
  4. 4. The AC Method / Cross Method for Quadratics:

    When factoring a trinomial $ax^2 + bx + c$ where the leading coefficient $a \neq 1$, trial and error is frustrating. The Cross Method (AC Method) is a visual algorithm that guarantees success. You pair factors of $a$ and factors of $c$, cross-multiply them, and ensure their sum matches the middle term $b$.

    Factor: $6x^2 + 11x - 10$

    Factors of a (6) Factors of c (-10) Cross Products 2 3 5 -2 3 × 5 = 15 2 × -2 = -4 Sum = 11 (Matches b!)

    Since the sum matches the middle term $11x$, we read the factors horizontally row by row.

    Result: $(2x + 5)(3x - 2)$

4.1 The Factor Theorem

If you are dealing with a polynomial $P(x)$ of degree 3 or higher, and grouping doesn't work, you must use the Factor Theorem. The theorem states: If you plug a number $c$ into the polynomial and the result is zero (i.e., $P(c) = 0$), then $(x - c)$ is guaranteed to be a factor.

Example: Factor $P(x) = x^3 - 7x + 6$

Step 1: Guess values for $x$ that are divisors of the constant term (6). Let's test $\pm 1, \pm 2, \pm 3$.

Test x=1: $P(1) = 1^3 - 7(1) + 6 = 1 - 7 + 6 = 0$.

Since $P(1) = 0$, the Factor Theorem tells us that $(x - 1)$ is a factor.

Step 2: To find the remaining quadratic factor, divide the original polynomial by $(x - 1)$ using Polynomial Long Division (which we will cover in the next section).

The division yields $x^2 + x - 6$.

Step 3: Factor the resulting quadratic: $x^2 + x - 6 = (x + 3)(x - 2)$.

Final complete factorization: $P(x) = (x - 1)(x - 2)(x + 3)$

IMAT Challenge

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Official Paper: 2020 - Q56

Given the following exponential equation, what is the value of x? $$8^{2x+3} \times \frac{1}{4^{3x}} = 2^{x+3}$$
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Official Paper: 2015 - Q58

Evaluate: $$(27^2-23^2)+(14^2-6^2)$$
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Official Paper: 2021 - Q53

Which one of the following is a simplification of: $$\frac{(x+2)^2}{x^2+x-2}$$

Part 5: Solving Equations & Polynomial Division

An equation $f(x) = 0$ is a question: "At what exact points does the graph of this mathematical function cross the horizontal x-axis?" Solving an equation is finding those roots.

5.1 Quadratic Equations & The Discriminant

When a quadratic equation $ax^2 + bx + c = 0$ cannot be factored easily, the Quadratic Formula is the universal tool.

The Quadratic Formula: $$ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} $$

The value inside the square root, $D = b^2 - 4ac$, is called the Discriminant. It fundamentally controls the nature of the roots by determining what happens when you add or subtract the square root.

Visualizing the Discriminant's Effect on the Parabola

Case 1: $D > 0$

$\sqrt{Positive}$ yields a real value. You step left and right from the vertex.
Two Real Roots.

Case 2: $D = 0$

$\pm \sqrt{0}$ adds nothing. The vertex sits exactly on the axis.
One Repeated Root.

Case 3: $D < 0$

$\sqrt{Negative}$ is not a Real number. The graph never touches the axis.
No Real Roots.

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Official Paper: 2025 - Q53

For which values of $a$ is the equation determined? $$3x+a=3$$
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Official Paper: 2025 - Q54

Given the equation, which of the following values of $a$ is impossible? $$(a+3)x=5$$
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Official Paper: 2024 - Q51

Which of the following is the solution of the inequality $$\frac{4-3x}{x^2+|4x+3|} \ge 0$$
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Official Paper: 2020 - Q57

39 male students and 36 female students were asked how many meals they had eaten... Overall mean is $ 3\frac{1}{5} $, Male mean is 2. What is female mean x?
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Official Paper: 2015 - Q55

The variables x and y satisfy: $x+3y=13$ and $2x-y=5$. What is the value of $ x+y $?

5.2 Biquadratic Equations

Equations of the form $ax^4 + bx^2 + c = 0$ appear terrifying because of the 4th power, but they are secretly quadratics in disguise. You solve them using a mathematical technique called substitution.

Example: Solve $x^4 - 13x^2 + 36 = 0$

  1. Let a new variable, $y = x^2$. Consequently, $y^2 = x^4$.
  2. Substitute $y$ into the original equation to transform it:
       $y^2 - 13y + 36 = 0$
  3. This is now a standard quadratic! Factor it:
       $(y - 9)(y - 4) = 0 \implies y = 9$ or $y = 4$
  4. Crucial Step: Reverse the substitution. You are solving for $x$, not $y$.
       If $y = 9 \implies x^2 = 9 \implies \mathbf{x = \pm 3}$
       If $y = 4 \implies x^2 = 4 \implies \mathbf{x = \pm 2}$
  5. The equation has four distinct real solutions: $x = -3, -2, 2, 3$.

5.3 Polynomial Long Division

When applying the Factor Theorem, you must divide a larger polynomial by a known linear factor to find the remaining polynomial. Polynomial Long Division works exactly like elementary numerical long division.

Example: Divide $(2x^3 - 5x^2 + 8x - 4)$ by $(x - 1)$

2x² - 3x + 5 <-- Quotient ___________________ (x - 1) | 2x³ - 5x² + 8x - 4 <-- Dividend -(2x³ - 2x²) <-- Multiply (x-1) by 2x² ------------ - 3x² + 8x <-- Subtract and bring down 8x -(- 3x² + 3x) <-- Multiply (x-1) by -3x ------------- 5x - 4 <-- Subtract and bring down -4 -(5x - 5) <-- Multiply (x-1) by 5 -------- 1 <-- Remainder

Therefore, the result is: $\mathbf{2x^2 - 3x + 5 + \frac{1}{x-1}}$

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Official Paper: 2023 - Q55

The expression simplifies to which of the following? $$\sqrt{\frac{16^x+8^x}{4^x+2^x}}$$
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Official Paper: 2016 - Q55

Which one of the following is a simplification of: $$ \frac{2}{x^2-1} - \frac{1}{x-1} $$

5.4 Rational and Radical Equations (The Threat of Extraneous Roots)

WARNING: Extraneous Solutions (Ghost Roots)

Certain algebraic operations—specifically multiplying by a variable expression or squaring both sides of an equation—can mathematically create "ghosts". These are numbers that perfectly solve your final algebraic step, but cause a catastrophic error (like division by zero) or a logical impossibility in the original equation.

You must check your answers in the original equation!

Rational Example

Solve: $\frac{x}{x-2} - \frac{2}{x+1} = \frac{6}{x^2 - x - 2}$

  • 1. Factor Denominators: The right side $x^2 - x - 2$ factors to $(x-2)(x+1)$. Thus, the LCD is $(x-2)(x+1)$.
    Crucial restrictions: $x \neq 2$ and $x \neq -1$.
  • 2. Multiply by LCD to clear fractions:
       $x(x+1) - 2(x-2) = 6$
  • 3. Solve the resulting equation:
       $x^2 + x - 2x + 4 = 6$
       $x^2 - x - 2 = 0$
       $(x-2)(x+1) = 0 \implies x=2, x=-1$
  • 4. Check against restrictions: Both mathematical answers violate the initial constraints (they cause division by zero).
  • Final Result: No Real Solution.

Radical Example

Solve: $\sqrt{x} = -3$

  • 1. Conceptual Check: The principal square root function $\sqrt{x}$ always yields a positive number or zero. It can never equal -3. The equation is logically false. Let's see what happens if we blindly calculate.
  • 2. Square both sides:
       $(\sqrt{x})^2 = (-3)^2$
  • 3. Solve:
       $x = 9$
  • 4. Check the ghost root: Plug $x=9$ back into the original equation:
       $\sqrt{9} = 3$. But the equation demands it equal $-3$.
       $3 \neq -3$.
  • Final Result: No Real Solution.
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Official Paper: 2020 - Q53

Which of the following is equal to: $$\frac{2}{2+\sqrt{3}}$$
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Official Paper: 2014 - Q56

Evaluate: $$\frac{8\times10^{-5}}{\sqrt{1.6\times10^7}} \times (1.2\times10^3)^2$$

Part 6: Flawless Inequalities & The Wavy Curve Method

The Golden Rule of Inequalities

If you multiply or divide both sides of an inequality by a negative number, you MUST flip the inequality sign.

Multiplying by a negative reflects numbers across zero on the number line. While $5 > 2$ is true, multiplying by -1 reflects them to $-5$ and $-2$. Since $-5$ is further left, $-5 < -2$. The sign must flip.

6.1 Higher-Degree Polynomial Inequalities (The Wavy Curve Method)

When dealing with inequalities involving polynomials of degree 3 or higher, or complex rational fractions, calculating test values for every single interval takes too much time. The Wavy Curve Method (Sign Chart) is a powerful visual algorithm to solve these instantly.

Example: Solve $(x-1)(x+2)(x-4) > 0$

  1. Identify the Roots: Find where each factor equals zero. The roots are $x=1, x=-2,$ and $x=4$.
  2. Plot on a Number Line: Place these roots in ascending order on a number line.
  3. Draw the Wave: Start from the top right (positive infinity). Since all $x$ terms are positive ($+x$, not $-x$), the function starts positive. Draw a continuous wave that passes through each root, alternating from positive (above the line) to negative (below the line).
-2 1 4 - + - +

Select the correct regions: The inequality asks for values $> 0$ (strictly positive). We look at our wave and select the regions where the curve is above the number line.

Final Answer: $-2 < x < 1 \text{ or } x > 4$

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Official Paper: 2025 - Q48

What is the solution to the inequality: $$\sqrt{2x} \lt 1+x$$
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Official Paper: 2024 - Q48

The expression is equivalent to: $$(512^{(1/3)})^{(1/2)}$$
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Official Paper: 2015 - Q53

Given that $2\log_{10}(x) - 3 = \log_{10}(y)$. Express y in terms of x.

6.2 Fractional Inequalities: The Squaring Method

Consider the inequality $\frac{x-1}{x+3} \ge 0$. You cannot multiply both sides by the denominator $(x+3)$ because you do not know if $(x+3)$ is positive or negative. Depending on the unknown value of $x$, you might need to flip the inequality sign, which makes multiplication invalid.

Method: Multiplying by the Square of the Denominator

While we don't know the sign of $(x+3)$, we are absolutely certain that the square, $(x+3)^2$, is strictly positive (for any real number $x \neq -3$). Therefore, we can safely multiply both sides of the inequality by $(x+3)^2$ without ever violating the Golden Rule!

Solve: $\frac{x-1}{x+3} \ge 0$

1. State restriction: $x \neq -3$

2. Multiply by $(x+3)^2$:

$\frac{x-1}{x+3} \cdot \mathbf{(x+3)^2} \ge 0 \cdot \mathbf{(x+3)^2}$

3. Simplify (one $(x+3)$ cancels out):

$(x-1)(x+3) \ge 0$

4. Solve this standard quadratic (roots are 1 and -3, opens up, we want $\ge 0$):

$x \le -3 \text{ or } x \ge 1$

5. Apply the restriction from step 1 ($x \neq -3$):

$\mathbf{x < -3 \text{ or } x \ge 1}$

6.3 Absolute Value Equations and Inequalities

The absolute value $|X|$ geometrically represents the distance of a number $X$ from zero on the number line. Because distance is always positive, absolute value equations and inequalities naturally split into two separate scenarios.

"Sandwich" Distance

Distance is less than $a$. Must stay close to zero.

$$ |X| < a \implies -a < X < a $$

-a a

"Split" Distance

Distance is greater than $a$. Must be far from zero.

$$ |X| > a \implies X < -a \text{ or } X > a $$

-a a
IMAT Challenge

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Official Paper: 2024 - Q49

If $f(x) = \log_2(x^2+12)$ What is the reciprocal of $ f(2) $?
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Official Paper: 2019 - Q57

What is the highest common factor of 360, 500 and 700?

Part 7: Logarithms & Exponential Equations

If an exponent answers the question "What is the base multiplied by itself $y$ times?", a logarithm answers the reverse: "To what power $y$ must we raise the base $b$ to get the number $x$?"

The Fundamental Definition

$$ y = \log_b(x) \iff b^y = x $$

(Where base $b > 0$, $b \neq 1$, and argument $x > 0$)

The Laws of Logarithms

Because logarithms are the exact inverse of exponents, their laws are direct translations of the Laws of Indices.

  • Product Law: $\log_b(xy) = \log_b(x) + \log_b(y)$
    (Multiplication inside becomes addition outside).
  • Quotient Law: $\log_b(\frac{x}{y}) = \log_b(x) - \log_b(y)$
    (Division inside becomes subtraction outside).
  • Power Law: $\log_b(x^n) = n \cdot \log_b(x)$
    (Powers drop down to the front as multipliers).
  • Change of Base Formula: $\log_b(x) = \frac{\log_c(x)}{\log_c(b)}$
    (Allows evaluation on calculators using natural log (ln) or base 10).

Example: Solving an Exponential Equation using Logarithms

Solve for $x$: $5^{2x-1} = 7$

  1. Since the bases (5 and 7) cannot be made equal, we must "drop" the exponent down. Take the natural logarithm ($\ln$) of both sides:
       $\ln(5^{2x-1}) = \ln(7)$
  2. Use the Power Law of Logarithms to bring the exponent to the front:
       $(2x - 1) \cdot \ln(5) = \ln(7)$
  3. Divide both sides by $\ln(5)$ (which is just a constant number):
       $2x - 1 = \frac{\ln(7)}{\ln(5)}$
  4. Isolate $x$ using basic algebra:
       $2x = \frac{\ln(7)}{\ln(5)} + 1$
       $\mathbf{x = \frac{\frac{\ln(7)}{\ln(5)} + 1}{2}}$
IMAT Challenge

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Official Paper: 2023 - Q53

What is the complete set of values of x for which the following inequalities hold? $$100 - 99x \le 98 - 97x \quad \text{and} \quad 96 + 95x \gt 94 + 93x$$
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Official Paper: 2019 - Q58

What is the sum of the solutions to $$\frac{3}{x} + \frac{2}{x-2} = 1$$
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Official Paper: 2019 - Q59

Which of the following expressions is equal to $$ \frac{8^{2n} \times 4^n}{2^n} $$ for all integers n?
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Official Paper: 2017 - Q57

Given that $ \log_{10} 7 = x $, $ \log_{10} 2 = y $, $\log_{10} 3 = z$. What is $\log_{10}(\frac{14}{3})$ expressed in terms of x, y, and z?
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Official Paper: 2014 - Q58

A computer game is on sale for €32.00. The ticket shows this is a reduction of 20% of the original price. What was original price?
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Official Paper: 2013 - Q58

Simplify: $$\ln\left(\frac{x^2}{4y}\right) + \ln(xy) + \ln(8)$$
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Official Paper: 2013 - Q59

What is the set of values for which the following inequalities are true: $$12-x^2 \gt 8 \quad \text{and} \quad 2x+3 \ge 5$$
IMAT Challenge

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Official Paper: 2012 - Q76

Which of the following is equivalent to: $$\ln(x^2y) - 2\ln(xy) + 3\ln(y)$$

Part 8: Mathematical Translation (Word Problems)

A significant portion of the IMAT tests your ability to translate real-world English sentences into abstract algebraic equations. This requires mapping verbal relationships directly to mathematical operators.

8.1 Translation Dictionary

English Phrase Algebraic Translation
"Is", "Yields", "Results in" =
"Sum of", "More than", "Increased by" +
"Difference", "Less than", "Decreased by" -
"Product", "Of" (e.g., half of x) × or ·
"Quotient", "Per", "Out of" ÷ or /
"x is 5 less than y" x = y - 5 (Watch the order!)

8.2 Classic IMAT Problem Types

Age Problems

"A father is currently 3 times as old as his son. In 12 years, he will be exactly twice as old as his son. Find their current ages."

  • Setup Variables: Let son's current age = $x$. Thus, father's current age = $3x$.
  • Fast Forward 12 Years:
    Son's age = $x + 12$
    Father's age = $3x + 12$
  • Translate the relationship:
    $\text{Father's future age} = 2 \times (\text{Son's future age})$
    $(3x + 12) = 2(x + 12)$
  • Solve:
    $3x + 12 = 2x + 24$
    $x = 12$
  • Result: Son is 12, Father is 36.

Distance-Speed-Time

"A train travels 120km at speed V. If the speed were increased by 20km/h, the journey would take 1 hour less. Find V."

  • Recall Formula: $Time = \frac{Distance}{Speed}$
  • Original Time: $T_1 = \frac{120}{V}$
  • New Time: $T_2 = \frac{120}{V + 20}$
  • Translate "1 hour less":
    $T_1 - T_2 = 1$
    $\frac{120}{V} - \frac{120}{V + 20} = 1$
  • Solve (Multiply by LCD):
    $120(V+20) - 120V = V(V+20)$
    $2400 = V^2 + 20V$
    $V^2 + 20V - 2400 = 0 \implies (V-40)(V+60) = 0$
  • Result: Speed is 40 km/h (reject -60).

Part 9: Ultimate IMAT Mathematical Mastery (50 Questions)

This comprehensive diagnostic test covers every single concept taught in this module. From identifying prime numbers to expanding complex binomials, unwrapping double radicals, executing polynomial long division, and dissecting tricky word problems.

Instructions: Answer all 50 questions. Take your time. Once submitted, detailed step-by-step explanations will be revealed for every single question to help you analyze your mistakes.